com.example.UserServiceException: 用户注册模块发生内部错误 at com.example.UserService.registerUser(UserService.java:15) ... (省略中间调用栈) Caused by: java.lang.ArithmeticException: / by zero <--- 底层原因清晰可见 at com.example.UserService.registerUser(UserService.java:11) ...
publicstaticvoidmain(String args[]) { inta=10; intb=20; System.out.println("a == b = " + (a == b) ); System.out.println("a != b = " + (a != b) ); System.out.println("a > b = " + (a > b) ); System.out.println("a < b = " + (a < b) ); System.out.println("b >= a = " + (b >= a) ); System.out.println("b <= a = " + (b <= a) ); } }
结果
a == b = false a != b = true a > b = false a < b = true b >= a = true b <= a = false
publicclassTest { publicstaticvoidmain(String args[]) { inta=60; /* 60 = 0011 1100 */ intb=13; /* 13 = 0000 1101 */ intc=0; c = a & b; /* 12 = 0000 1100 */ System.out.println("a & b = " + c );
c = a | b; /* 61 = 0011 1101 */ System.out.println("a | b = " + c );
c = a ^ b; /* 49 = 0011 0001 */ System.out.println("a ^ b = " + c );
c = ~a; /*-61 = 1100 0011 */ System.out.println("~a = " + c );
c = a << 2; /* 240 = 1111 0000 */ System.out.println("a << 2 = " + c ); c = a >> 2; /* 215 = 1111 */ System.out.println("a >> 2 = " + c ); c = a >>> 2; /* 215 = 0000 1111 */ System.out.println("a >>> 2 = " + c ); } }
结果
a & b = 12 a | b = 61 a ^ b = 49 ~a = -61 a << 2 = 240 a >> 2 = 15 a >>> 2 = 15
逻辑运算符
1) a&b : & 叫逻辑与：规则：当 a 和 b 同时为 true ,则结果为 true, 否则为 false 2) a&&b : && 叫短路与：规则：当 a 和 b 同时为 true ,则结果为 true,否则为 false 3) a|b : | 叫逻辑或，规则：当 a 和 b ，有一个为 true ,则结果为 true,否则为 false 4) a||b : || 叫短路或，规则：当 a 和 b ，有一个为 true ,则结果为 true,否则为 false 5) !a : 叫取反，或者非运算。当 a 为 true, 则结果为 false, 当 a 为 false 是，结果为 true 6) a^b: 叫逻辑异或，当 a 和 b 不同时，则结果为 true, 否则为 false
对于&&短路与而言，如果第一个条件为 false ,后面的条件不再判断，效率高
对于&逻辑与而言，如果第一个条件为 false ,后面的条件仍然会判断，效率低
||短路或：如果第一个条件为 true，则第二个条件不会判断，最终结果为 true，效率高
| 逻辑或：不管第一个条件是否为 true，第二个条件都要判断，效率低
赋值运算符
示例
publicclassTest { publicstaticvoidmain(String args[]) { inta=10; intb=20; intc=0; c = a + b; System.out.println("c = a + b = " + c ); c += a ; System.out.println("c += a = " + c ); c -= a ; System.out.println("c -= a = " + c ); c *= a ; System.out.println("c *= a = " + c ); a = 10; c = 15; c /= a ; System.out.println("c /= a = " + c ); a = 10; c = 15; c %= a ; System.out.println("c %= a = " + c ); c <<= 2 ; System.out.println("c <<= 2 = " + c ); c >>= 2 ; System.out.println("c >>= 2 = " + c ); c >>= 2 ; System.out.println("c >>= a = " + c ); c &= a ; System.out.println("c &= a = " + c ); c ^= a ; System.out.println("c ^= a = " + c ); c |= a ; System.out.println("c |= a = " + c ); } }
结果
c = a + b = 30 c += a = 40 c -= a = 30 c *= a = 300 c /= a = 1 c %= a = 5 c <<= 2 = 20 c >>= 2 = 5 c >>= 2 = 1 c &= a = 0 c ^= a = 10 c |= a = 10
]]>Bitcoin is a decentralized digital currency that can be used without a centralized authority or bank. It uses peer-to-peer technology to allow users to send and receive money without the need for a financial institution.HTTPS页面请求HTTP接口失败？一文讲透Mixed Contenthttps://blog.itrf.cn/posts/ceca/2026-02-13T15:15:57.000Z2026-02-13T15:34:34.956ZHTTPS页面请求HTTP接口失败？一文讲透Mixed Content
MixedContent: The page at 'https://yourdomain.com' was loaded over HTTPS, but requested an insecure XMLHttpRequest endpoint 'http://your-server-ip:port/api'. This request has been blocked; the content must be served over HTTPS.
大模型的推理过程不是一步到位的，当大模型进行推理时，它会基于现有的token，根据概率最大原则预测出下一个最有可能的token，然后将该预测的token加入到输入序列中，并将更新后的输入序列继续输入大模型预测下一个token，这个过程叫做自回归。直到输出特殊token（如，end of sentence，专门用来控制推理何时结束）或输出长度达到阈值。
You are an AI language model assistant. Your task is to generate five different versions of the given user question to retrieve relevant documents from a vector database. By generating multiple perspectives on the user question, your goal is to help the user overcome some of the limitations of the distance-based similarity search. Provide these alternative questions separated by newlines. Original question: {question}
You are a helpful assistant that generates multiple sub-questions related to an input question. \n The goal is to break down the input into a set of sub-problems / sub-questions that can be answers in isolation. \n Generate multiple search queries related to: {question} \n Output (3 queries):
全参微调（Full Fine Tuning）是在预训练模型的基础上进行全量参数微调的模型优化方法，只要有参数，就会被调整。该方法避免消耗重新开始训练模型所有参数所需的大量计算资源，又能避免部分参数未被微调导致模型性能下降。但是，大模型训练成本高昂，需要庞大的计算资源和大量的数据，即使是全参数微调，往往也需要较高的训练成本。
input_variables=['agent_scratchpad', 'input', 'tool_names', 'tools'] template='Answer the following questions as best you can. You have access to the following tools:
{tools}
Use the following format:
Question: the input question you must answer Thought: you should always think about what to do Action: the action to take, should be one of [{tool_names}] Action Input: the input to the action Observation: the result of the action ... (this Thought/Action/Action Input/Observation can repeat N times) Thought: I now know the final answer Final Answer: the final answer to the original input question
]]>href属性中/的不同作用Linux 常用命令大全https://blog.itrf.cn/posts/bf2c/2025-10-29T05:06:38.000Z2026-01-27T16:35:29.563Z本文整理了 Linux 系统中文件操作、权限管理、系统监控、网络操作等高频命令，覆盖新手入门到日常运维场景，格式清晰可直接查阅。
一、文件与目录操作命令（最基础高频）
1. ls - 列出目录内容
功能：列出指定目录下的文件 / 目录，默认列出当前目录。核心参数：
-l（长格式）：显示文件权限、所有者、大小、修改时间等详细信息。
-a（all）：显示所有文件（含隐藏文件，以.开头）。
-h（human-readable）：以人类可读格式显示文件大小（如 KB、MB）。
-r（reverse）：反向排序（默认按字母升序）。
-t（time）：按修改时间排序（最新在前）。
示例：
ls -lha # 长格式显示当前目录所有文件，含隐藏文件，大小人性化显示 ls /home/user # 列出指定目录/home/user下的内容
2. cd - 切换工作目录
功能：切换当前终端的工作目录。核心用法：
cd 目录路径：切换到指定目录（绝对路径 / 相对路径）。
cd ~ 或 cd：切换到当前用户的家目录（如/home/ubuntu）。
cd ..：切换到上级目录。
cd -：切换到上一次所在的目录。
示例：
cd /etc/nginx # 绝对路径切换到nginx配置目录 cd ../logs # 相对路径切换到上级目录的logs子目录 cd ~/Documents # 切换到家目录的Documents文件夹
create [unique][clustered|nonclustered] index <index name>on<tableorview name>(<colum name>[ASC|DESC][,...n])
查看索引 （sys.indexes）
select*from sys.indexes where name ='索引名'
删除索引
drop index 索引名 on 表名
使用索引
select*from 表名 with (index=索引名) where 条件
视图
创建视图：
createview 视图名 asselect语句 go
查询视图：
select*from 视图名
删除视图：
dropview 视图名
游标
分类：
静态游标
动态游标
键集驱动游标
创建游标(scroll：滚动游标，没有scroll，只进)
declare 游标名 cursorscrollforselect 字段名 from 表名
打开游标
open 游标名
关闭游标
close 游标名
删除游标
deallocate 游标名
提取数据
fetchfirstfrom 游标名 --提取第一行 fetchlastfrom 游标名 --提取最后一行 fetch absolute 2from 游标名 --提取第二行 fetch relative 2from 游标名 --当前行下移两行 fetch next from 游标名 --下移一行 fetch prior from 游标名 --上移一行
—提取游标数据存放入变量，进行查询所有列信息
declare@accvarchar(20) fetch absolute 2from mycur into@acc select*from Menber where MenberAccount=@acc
—遍历游标
@@fetch_status ：0提取成功，-1提取失败，-2不存在 declare@accvarchar(20) fetch absolute 2from mycur into@acc while @@fetch_status=0 begin print'提取成功：'+@acc fetch next from mycur into@acc end
error: failed to push some refs to 'http://xxxx.cn/vip/xxx.git' To http://xxxx.cn/vip/xxx.git !refs/heads/master:refs/heads/master[rejected] (fetch first) Done hint: Updates were rejected because the remote contains work that you do not hint: have locally. This is usually caused by another repository pushing to hint: the same ref. If you want to integrate the remote changes, use hint: 'git pull' before pushing again.
或简化版错误：
[rejected] master -> master (fetch first) error: failed to push some refs
